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13x-3x^2=-88
We move all terms to the left:
13x-3x^2-(-88)=0
We add all the numbers together, and all the variables
-3x^2+13x+88=0
a = -3; b = 13; c = +88;
Δ = b2-4ac
Δ = 132-4·(-3)·88
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-35}{2*-3}=\frac{-48}{-6} =+8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+35}{2*-3}=\frac{22}{-6} =-3+2/3 $
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